Cable Voltage Drop Calculator

Voltage drop is usually quoted as a single figure, which hides the fact that on a long run at poor power factor the reactive term can rival the resistive one. This separates the two, so you can see whether a bigger conductor will actually help.

Voltage drop along a run, split into resistive and reactive parts sourceRXloadcos phiIL, one way dV = k I L (R cos phi + X sin phi) k = sqrt(3) three phase, 2 otherwise
A bigger conductor shrinks only the resistive term. If the reactive part dominates, correct the power factor instead - more copper will not help.

Inputs — enter your values

The factor for flow and return is applied automatically.

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In milliohm per metre, per conductor. 95 mm2 copper is about 0.193, 120 mm2 about 0.153.

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In milliohm per metre. Around 0.08 for typical multicore cable at 50 Hz, higher for spaced singles.

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Results — computed for you

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Percent of nominal. Common design limits are 3% for lighting and 5% for power.

The part a larger conductor reduces.

Barely improves with conductor size. If this dominates, correct the power factor instead.

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sqrt(3) for three phase, 2 for single phase and DC.

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Choosing something to solve for makes Voltage drop an editable target and computes the chosen input from it.

Formula

dV = k I L (R cos(phi) + X sin(phi)) k = sqrt(3) three phase, 2 single phase and DC Loss = m I^2 R L, m = 3 three phase, 2 otherwise
R, X resistance and reactance per unit length of one conductor
L one-way run length (m)
phi load displacement angle, cos(phi) is the power factor
k supply arrangement factor

What this model assumes, and where it stops

Assumptions

  • Balanced load and balanced three-phase currents.
  • Sinusoidal current at the fundamental only.
  • Constant resistance and reactance along the run, at the operating temperature.
  • Displacement power factor - no harmonic distortion.
  • A single load at the far end, not distributed along the run.

Limitations

  • Conductor resistance rises about 0.4% per kelvin. Cable tables are usually quoted at the maximum conductor temperature, so using a 20 degC value understates the drop on a fully loaded circuit.
  • Reactance depends strongly on conductor spacing and arrangement. Spaced single-core cables have several times the reactance of a multicore, and a single tabulated value cannot cover that.
  • Harmonics raise both the loss and the effective impedance, and neither is represented here.
  • For a distributed load, the drop is roughly half what a lumped end load gives - this page assumes the end load.
  • The exact phasor solution differs slightly from this linear approximation at large drops; above about 10% the approximation starts to matter.
  • Nothing here checks ampacity, derating or protection coordination, which are usually the binding constraints.

When you need a 3D field solution instead

Closed-form models like the one above hold on idealised geometry. These are the cases where they stop being good enough and a full 3D electromagnetic and thermal solution is the only way to get a trustworthy answer:

  • Working out the actual reactance of a specific conductor arrangement rather than taking a table value.
  • Busbar systems where geometry sets the inductance and the phases couple strongly.
  • Harmonic-rich loads, where skin and proximity effects raise the effective resistance frequency by frequency.
  • Parallel cable runs, where circulating currents and unequal sharing depend on the physical layout.
  • Cases needing the magnetic field around the run as well as the drop along it.

Common questions

What voltage drop is acceptable?

Installation codes typically allow 3 to 5% total from origin to load, split between feeder and final circuit - IEC 60364-5-52 suggests 4% as a default and separate limits apply for motor starting. The right number is the one your equipment tolerates: drives and contactors care about the voltage at their terminals during inrush, not the steady-state figure.

Why does doubling the conductor size not halve my voltage drop?

Because only the resistive part scales with copper. In the default 100 A, 50 m case at 95 mm2 the drop is 1.71 V of which 79% is resistive; going to 300 mm2 leaves 0.81 V, but the resistive share falls to 55% and the reactive part - set by conductor spacing, not size - stays at 0.36 V. Past that point you fix voltage drop with power factor correction or shorter routes, not more copper.

Where do the factor 2 and the factor sqrt(3) come from?

Single-phase current flows out and back, so the drop acts over twice the one-way length. In a balanced three-phase system the return currents cancel in the neutral and the line-to-line drop works out to sqrt(3) times the one-way per-conductor drop. The calculator applies the right factor from the supply selection; the length you enter is always one-way.

References

  • IEC 60364-5-52 - Electrical installations, selection and erection of wiring systems
  • IEC 60287 - Electric cables, calculation of the current rating

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