Cable Voltage Drop Calculator

Voltage drop is usually quoted as a single figure, which hides the fact that on a long run at poor power factor the reactive term can rival the resistive one. This separates the two, so you can see whether a bigger conductor will actually help.

Voltage drop along a run, split into resistive and reactive parts sourceRXloadcos phiIL, one way dV = k I L (R cos phi + X sin phi) k = sqrt(3) three phase, 2 otherwise
A bigger conductor shrinks only the resistive term. If the reactive part dominates, correct the power factor instead - more copper will not help.

Inputs — enter your values

The factor for flow and return is applied automatically.

In milliohm per metre, per conductor. 95 mm2 copper is about 0.193, 120 mm2 about 0.153.

In milliohm per metre. Around 0.08 for typical multicore cable at 50 Hz, higher for spaced singles.

Results — computed for you

Percent of nominal. Common design limits are 3% for lighting and 5% for power.

The part a larger conductor reduces.

Barely improves with conductor size. If this dominates, correct the power factor instead.

sqrt(3) for three phase, 2 for single phase and DC.

Choosing something to solve for makes Voltage drop an editable target and computes the chosen input from it.

Formula

dV = k I L (R cos(phi) + X sin(phi)) k = sqrt(3) three phase, 2 single phase and DC Loss = m I^2 R L, m = 3 three phase, 2 otherwise
R, X resistance and reactance per unit length of one conductor
L one-way run length (m)
phi load displacement angle, cos(phi) is the power factor
k supply arrangement factor

What this model assumes, and where it stops

Assumptions

  • Balanced load and balanced three-phase currents.
  • Sinusoidal current at the fundamental only.
  • Constant resistance and reactance along the run, at the operating temperature.
  • Displacement power factor - no harmonic distortion.
  • A single load at the far end, not distributed along the run.

Limitations

  • Conductor resistance rises about 0.4% per kelvin. Cable tables are usually quoted at the maximum conductor temperature, so using a 20 degC value understates the drop on a fully loaded circuit.
  • Reactance depends strongly on conductor spacing and arrangement. Spaced single-core cables have several times the reactance of a multicore, and a single tabulated value cannot cover that.
  • Harmonics raise both the loss and the effective impedance, and neither is represented here.
  • For a distributed load, the drop is roughly half what a lumped end load gives - this page assumes the end load.
  • The exact phasor solution differs slightly from this linear approximation at large drops; above about 10% the approximation starts to matter.
  • Nothing here checks ampacity, derating or protection coordination, which are usually the binding constraints.

When you need a 3D field solution instead

Closed-form models like the one above hold on idealised geometry. These are the cases where they stop being good enough and a full 3D electromagnetic and thermal solution is the only way to get a trustworthy answer:

  • Working out the actual reactance of a specific conductor arrangement rather than taking a table value.
  • Busbar systems where geometry sets the inductance and the phases couple strongly.
  • Harmonic-rich loads, where skin and proximity effects raise the effective resistance frequency by frequency.
  • Parallel cable runs, where circulating currents and unequal sharing depend on the physical layout.
  • Cases needing the magnetic field around the run as well as the drop along it.

Common questions

What voltage drop is acceptable?

Installation codes typically allow 3 to 5% total from origin to load, split between feeder and final circuit - IEC 60364-5-52 suggests 4% as a default and separate limits apply for motor starting. The right number is the one your equipment tolerates: drives and contactors care about the voltage at their terminals during inrush, not the steady-state figure.

Why does doubling the conductor size not halve my voltage drop?

Because only the resistive part scales with copper. In the default 100 A, 50 m case at 95 mm2 the drop is 1.71 V of which 79% is resistive; going to 300 mm2 leaves 0.81 V, but the resistive share falls to 55% and the reactive part - set by conductor spacing, not size - stays at 0.36 V. Past that point you fix voltage drop with power factor correction or shorter routes, not more copper.

Where do the factor 2 and the factor sqrt(3) come from?

Single-phase current flows out and back, so the drop acts over twice the one-way length. In a balanced three-phase system the return currents cancel in the neutral and the line-to-line drop works out to sqrt(3) times the one-way per-conductor drop. The calculator applies the right factor from the supply selection; the length you enter is always one-way.

References

  • IEC 60364-5-52 - Electrical installations, selection and erection of wiring systems
  • IEC 60287 - Electric cables, calculation of the current rating

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